Let a differentiable function f satisfy the equation ∫₀³⁶ f(tx/36) dt = 4α f(x) || JEE Main 2026 скачать в хорошем качестве

Let a differentiable function f satisfy the equation ∫₀³⁶ f(tx/36) dt = 4α f(x) || JEE Main 2026

Q14. JEE Main 2026 (24 January Shift 1) Let a differentiable function f satisfy the equation ∫₀³⁶ f(tx/36) dt = 4α f(x) If y = f(x) is a standard parabola passing through the points (2,1) and (−4, β), then βᵅ is equal to ______. In this video you will learn: • Trick to simplify definite integrals with substitution • Concept of standard parabola in coordinate geometry • Using given points to determine the function • Smart solving techniques for JEE Main maths questions This problem is helpful for students preparing for: JEE Main 2026 JEE Main 2027 JEE Advanced Watch till the end to understand the complete step-by-step solution and shortcut approach used in competitive exams. Tags: jee main 2026 maths question, jee main 24 january shift 1 solution, definite integral jee main, standard parabola jee question, functional equation jee maths, jee main maths solved questions, calculus and coordinate geometry jee, jee previous year maths questions, jee maths tough question Hashtags: #JEEMain2026 #JEE2026 #JEEMaths #Calculus #DefiniteIntegral #CoordinateGeometry #MathsTricks #JEEPreparation #EngineeringEntrance