COUNT UNHAPPY FRIENDS (Leetcode) - Code & Whiteboard скачать в хорошем качестве

COUNT UNHAPPY FRIENDS (Leetcode) - Code & Whiteboard

A tricky Bloomberg favourite! Thankfully, the solution itself is quite succinct :) Time Complexity: O(n^2). For each of the n people, we will walk through (up to) n-1 entries in their preferences. Therefore, n * (n-1) approaches O(n^2). Space Complexity: O(n^2). We will have n entries in the dictionary we create, and each one of those can have (up to) n-1 entries in the set. Therefore, n * (n-1) approaches O(n^2). Let me know if you have any questions below! :) https://leetcode.com/problems/count-u... --------------------------------------------------------------------------------------------------------------------------------------------------------------- Let's connect on LinkedIn!   / aleksmitrovic   Follow me on Medium!   / mitrovic.aleksandar   Questions or suggestions for new videos? Email me! babybear4812@gmail.com