Irodov Solution 2.10 || Thermodynamics || IIT JEE || Olympiad Training || скачать в хорошем качестве

Irodov Solution 2.10 || Thermodynamics || IIT JEE || Olympiad Training ||

A smooth vertical tube having two different sections is open from both ends and equipped with two pistons of different areas (Fig). Each piston slides within a respective tube section. One mole of ideal gas is enclosed between the pistons tied with a non-stretchable thread. The cross-sectional area of the upper piston is ∆𝑆=10 〖𝑐𝑚〗^2 greater than that of the lower one. The combined mass of the two pistons is equal to 𝑚=5.0 𝑘𝑔. The outside air pressure is 𝑃_0=1 𝑎𝑡𝑚. By how many kelvins must the gas between the pistons be heated to shift the pistons through 𝑙=5.0 𝑐𝑚? https://drive.google.com/file/d/14DLq... #irodovsolutions #thermodynamics #jeeadvanced #apphysics #physicsolympiad #iitjee #class11physics #jeemains #physics #mechanics #jeemain #jeeadvanced2026