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Today's LeetCode Daily Problem: You are given an m by n integer grid. A rhombus sum is defined as the sum of the numbers forming the border of a rhombus shape in the grid. The rhombus looks like a square rotated 45 degrees. Goal Find the three largest distinct rhombus border sums in the grid. If there are fewer than three distinct sums, return all available sums. Core Idea Each cell can act as the center of a rhombus. Step 1 For every cell in the grid, consider it as the center. Step 2 Rhombus size 0 means the rhombus consists of only the single cell. Step 3 For larger rhombus sizes, expand outward while staying inside the grid boundaries. Step 4 Traverse the four edges of the rhombus and compute the border sum. Edges of rhombus Top to right Right to bottom Bottom to left Left to top Step 5 Store all unique sums in a TreeSet. Step 6 Extract the three largest values from the set. Why TreeSet It automatically keeps values sorted and removes duplicates. Time Complexity Approximately O(m multiplied by n multiplied by min(m,n)) Space Complexity O(k) for storing unique rhombus sums. Concepts Used Matrix traversal Simulation of shapes Sorted set for top values Problem Link https://leetcode.com/problems/get-big... Java Solution (GitHub) https://github.com/Amandf/LeetCode-So... Daily LeetCode grind continues #leetcode #leetcodesolution #leetcodedailychallenge #java #matrix #dsa #coding #programming #problemsolving #codinginterview