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Discover how to effortlessly create `shared_ptr` without the verbosity of specifying base classes in C+ + . Learn to use `std::make_shared` for cleaner and safer memory management. --- This video is based on the question https://stackoverflow.com/q/65321594/ asked by the user 'jpo38' ( https://stackoverflow.com/u/3336423/ ) and on the answer https://stackoverflow.com/a/65321790/ provided by the user 'eerorika' ( https://stackoverflow.com/u/2079303/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions. Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Is there no way to have shared_ptr be silently created? Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l... The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license. If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com. --- Simplifying shared_ptr Creation in C+ + : A Clear Solution with std::make_shared In the world of C+ + , memory management can be a complex task. With smart pointers like shared_ptr, developers gain a powerful tool for managing the heap allocations of objects without worrying about manual memory deallocation. However, there are moments when creating a shared_ptr can seem overly verbose, especially when working with inheritance hierarchies. In this blog, we’ll explore a common issue with the creation of shared_ptr and how to efficiently address it. The Challenge with shared_ptr Consider the following code snippet that illustrates a typical scenario where you want to pass a pointer to a base class (A) using a derived class (B): [[See Video to Reveal this Text or Code Snippet]] In this example, the line std::shared_ptr<A>(new B) is verbose and requires you to specify the base class (A) explicitly. This can become cumbersome, especially in cases where A is located deep within a namespace or when dealing with complex code structures. Is there a simpler way to achieve this without the additional boilerplate? Many developers have wished for something akin to std::make_pair, which allows type deduction for pairs without explicit type specifications. Enter std::make_shared The good news is, there is indeed a solution that fits this use case perfectly: std::make_shared. While one might initially think that std::make_shared isn’t suitable for this purpose, it actually is an ideal fit when used correctly. Using std::make_shared Instead of specifying the base type while creating a shared_ptr, you can utilize std::make_shared like so: [[See Video to Reveal this Text or Code Snippet]] Advantages of std::make_shared: Type Deduction: You don't need to specify the base class. The type B is automatically recognized, simplifying the syntax significantly. Memory Efficiency: std::make_shared allocates memory for both the object and the control block in a single allocation, which is generally more efficient on memory usage and performance. Safety: Using raw pointers (new) to create a shared_ptr can lead to issues like undefined behavior in scenarios where the base class is non-polymorphic (as in the initial example). By using std::make_shared, you can avoid these pitfalls. Conclusion To sum it up, the need to specify the type of the base class when creating a shared_ptr can clutter your code and introduce potential risks. By utilizing std::make_shared, you can not only simplify your syntax but also enhance the safety and performance of your memory management practices. So next time you find yourself needing to create a shared_ptr, remember that std::make_shared might be the clean, efficient solution you’re looking for. Embrace the elegance of C+ + with this simple change—your future self (and your co-developers) will thank you!