Chem 11 | Chap 10 | Lecture 6 | Oxidation number method| Example 10.4 Solved | New Syllabus скачать в хорошем качестве

Chem 11 | Chap 10 | Lecture 6 | Oxidation number method| Example 10.4 Solved | New Syllabus

Class 11 Chemistry | Chapter 10 – Oxidation Number Method (Balancing Redox Reactions) In this lecture, I explain the Oxidation Number Method used to balance redox reactions from Class 11 Chemistry Chapter 10 according to the new syllabus. The lecture begins with a clear explanation of the concept of oxidation and reduction in terms of oxidation numbers. After introducing the concept, I demonstrate the step-by-step procedure for balancing redox reactions using the oxidation number method, which is very important for board examinations. To make the concept clear, I also solve Example 10.4 from the textbook. In this example, the chemical reaction between potassium dichromate and hydrochloric acid is balanced using the oxidation number method. Unbalanced equation: K₂Cr₂O₇ + HCl → KCl + CrCl₃ + Cl₂ + H₂O Students will learn: • How to determine oxidation numbers of elements • How to identify oxidation and reduction in the reaction • How electron loss and gain are balanced • The correct step-by-step method to balance the redox equation This lecture is very helpful for Class 11 / FSc Part 1 students preparing for board examinations and concept building in electrochemistry. If the lecture helps you understand the topic, please like, share, and subscribe for more chemistry lectures and exam preparation content. #ChemistryClass11 #Chapter10Chemistry #RedoxReactions #OxidationNumberMethod #FScChemistry #Electrochemistry