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LeetCode 3713 | Longest Balanced Substring I | Daily LeetCode | Day 43/365 | C++ Solution In this video, we solve LeetCode 3713: Longest Balanced Substring I, where a substring is considered balanced if all distinct characters appear the same number of times. This is not a simple frequency check — we need an efficient way to track character counts dynamically and detect when a substring becomes balanced. 🧠 Core Idea: • Maintain running frequency counts of characters • Normalize frequencies to create a state representation • Use a hash map to store previously seen states • When the same state appears again → the substring between them is balanced 📌 What you’ll learn in this video: • How to convert a complex substring condition into a prefix-state problem • Why brute force won’t pass for large inputs • Smart use of hashing for substring detection • Clean and optimized C++ implementation • Time & space complexity explanation ⏱ Time Complexity: O(n × 26) 💾 Space Complexity: O(n) 💻 Problem Link: https://leetcode.com/problems/longest... 🎯 Why this problem matters: This is a powerful prefix + hashing pattern problem that builds strong intuition for advanced string and frequency-based problems — very useful for interviews and contests. 👍 Like the video if advanced string problems are getting clearer 💬 Comment if you want a dry run on a sample input 🔔 Subscribe for the 365 Days of LeetCode Challenge #LeetCode #DailyLeetCode #Day43of365 #Strings #Hashing #PrefixTechnique #CPlusPlus #DSA #InterviewPreparation