JEE Advanced 2013 | ITF PYQ | Maths PYQ | Full Concepts Explain скачать в хорошем качестве

JEE Advanced 2013 | ITF PYQ | Maths PYQ | Full Concepts Explain

The value of Cot(∑_(n=1)^23▒cot^(-1)⁡(1+∑_(k=1)^n▒2k) ) (A) 23/25 (B) 25/23 (C) 23/24 (D) 24/23 JEE Advanced 2013 JEE Advanced 2013 Inverse Trigonometric Functions (ITF) PYQ – a beautiful concept-based question that is still repeating in recent JEE papers. Question: The value of \cot\left(\sum_{n=1}^{23}\cot^{-1}\left(1+\sum_{k=1}^{n}2k\right)\right) is equal to: (A) 23/25 (B) 25/23 (C) 23/24 (D) 24/23 In this video, Amit Rathore Sir explains a smart telescoping ITF trick that converts a long summation into a single cot value within seconds. This is a must-know concept for JEE Advanced aspirants and is frequently used in PYQs of: • Inverse Trigonometric Functions • Summation based identities • Telescoping series in ITF If you are preparing for JEE Advanced 2026/2027, this concept can directly save you time in the exam. 🔥 Kota-style concept clarity 🔥 Short trick + full explanation 🔥 Useful for JEE Main + Advanced Subscribe for more high-level JEE Maths PYQs and rank-boosting concepts.