If 𝒙=(𝟓−√𝟐𝟏)/𝟐, the prove that (𝒙^𝟑+𝟏/𝒙^𝟑 )−𝟓(𝒙^𝟐+𝟏/𝒙^𝟐 )+(𝒙+𝟏/𝒙)=𝟎 скачать в хорошем качестве

If 𝒙=(𝟓−√𝟐𝟏)/𝟐, the prove that (𝒙^𝟑+𝟏/𝒙^𝟑 )−𝟓(𝒙^𝟐+𝟏/𝒙^𝟐 )+(𝒙+𝟏/𝒙)=𝟎

Class IX Polynomials Q: If x=(5-√21)/2, the prove that (x^3+1/x^3 )-5(x^2+1/x^2 )+(x+1/x)=0 Previous Videos related to this chapter are mentioned in the below link: COMPLETE NCERT EXERCISE | 2.2:    • COMPLETE NCERT EXERCISE | 2.2   COMPLETE NCERT EXERCISE | 2.3:    • COMPLETE NCERT EXERCISE | 2.3   INTRODUCTION TO POLYNOMIALS:    • INTRODUCTION TO POLYNOMIALS   CONCEPT: REMAINDER THEOREM & FACTOR THEOREM:    • CONCEPT: REMAINDER THEOREM & FACTOR THEOREM   CONCEPT: SPLITTING THE MIDDLE TERM:    • CONCEPT: SPLITTING THE MIDDLE TERM   QUESTIONS BASED ON IDENTITY:    • QUESTIONS BASED ON IDENTITY:(a±b)^3=a^3±3a...   (a±b)^3=a^3±3a^2 b+3ab^2±b^3 "or " a^3±b^3±3ab(a±b) QUESTIONS BASED ON IDENTITY:    • QUESTIONS BASED ON IDENTITY:a^3+b^3=(a+b)(...   a^3+b^3=(a+b)(a^2-ab+b^2 ) a^3-b^3=(a-b)(a^2+ab+b^2 ) QUESTIONS BASED ON IDENTITY:    • QUESTIONS BASED ON IDENTITY:a^3+b^3+c^3-3a...   a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca) *If a+b+c=0 "or" a^2+b^2+c^2-ab-bc-ca=0 then a^3+b^3+c^3=3abc QUESTIONS BASED ON MIDDLE TERM SPLITTING:    • QUESTIONS BASED ON MIDDLE TERM SPLITTING   COMPLETE NCERT EXERCISE | 2.1:    • COMPLETE NCERT EXERCISE | 2.1   CONCEPT: Zero of a Polynomial:    • CONCEPT: Zero of a Polynomial   Q: If a^2+b^2+c^2-ab-bc-ca=0. Prove that a=b=c:    • Q: If a^2+b^2+c^2-ab-bc-ca=0. Prove that a...   Q Prove that a^2+b^2+c^2-ab-bc-ca is always non negative for all value of a ,b &c:    • Q Prove that a^2+b^2+c^2-ab-bc-ca is alway...   Q Simplify: (x^3-3x^2-x)(x^2-3x+1):    • Q Simplify: (x^3-3x^2-x)(x^2-3x+1)   Q Prove that 2a^2+2b^2+2c^2-2ab-2bc-2ca=(a-b)^2+(b-c)^2+(c-a)^2:    • Q Prove that 2a^2+2b^2+2c^2-2ab-2bc-2ca=(a...   NCERT EXEMPLAR EXERCISE = 2.4 |ONE SHOT|    • NCERT EXEMPLAR EXERCISE - 2.4 |ONE SHOT|   Q: If x=(7-√45)/2, the prove that (x^3+1/x^3 )+(x+1/x)=7(x^2+1/x^3 )    • If 𝒙=(𝟕−√𝟒𝟓)/𝟐, the prove that (𝒙^𝟑+𝟏/𝒙^𝟑 ...   #CBSE #ICSE #Boards #8th #9th #10th #Foundation #Competition #IIT #JEE #Advanced #Mains #NTSE #Olympiads #Exams #Examination #Achiever #Topper #Zenith #ZenithInstituteOfMathematics #InderSir #Ludhiana #ModelGram #BestMathsCoaching #BestTutorials #BestTuition #BestInLudhiana #MathTricks #VIII #IX #X #XI #XII #Important #Excellent #Question #Polynomials #SolutionsOfEquations #RemainderTheorem #FactorTheorem #SplittingTheMiddleTerm