JEE Main 2026 Thermochemistry Question | Isothermal Work | Reversible Expansion скачать в хорошем качестве

JEE Main 2026 Thermochemistry Question | Isothermal Work | Reversible Expansion

Welcome to Padho Likho JEE! JEE Main 2026 Chemistry Question | Thermochemistry Question: 20.0 dm³ of an ideal gas X at 600 K and 0.5 MPa undergoes isothermal reversible expansion until the pressure becomes 0.2 MPa. Which of the following option is correct? (Given: log 2 = 0.3010 and log 5 = 0.6990) In this video, we solve a JEE Main 2026 thermochemistry question involving reversible isothermal expansion using the work formula: W = nRT ln(V₂/V₁) This problem tests concepts of: • Isothermal process • Ideal gas equation • Work done in reversible expansion • Sign convention in thermodynamics Padho Likho JEE — Concept First Learning If you found this video helpful, please like, share, and subscribe to our channel for more content on JEE and NEET preparation. Got questions or need further clarification? Leave a comment below, and we’ll be happy to help! #padholikhojee#JEEMain2026 #JEEChemistry #Thermodynamics #IsothermalProcess #IsothermalWork #ChemistryNumerical #JEEMainQuestions #PhysicalChemistry #JEEPreparation #PadhoLikhoJEE #NCERTChemistry #IITJEE #JEEMains2026 #ChemistryConcept #ExamQuestion