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What are the only positive integers 'k' for which the average of the k-th powers of the binomial coefficients is always an integer? This classic problem from the USA Mathematical Olympiad (USAMO) sits at the beautiful intersection of number theory and combinatorics. In this video, we provide a full, step-by-step proof to determine all possible values of k. We start by testing simple cases, then use powerful tools like modular arithmetic and Lucas's Theorem to find a necessary condition. We'll prove that all odd integers fail, and then show rigorously why all even integers are solutions, touching on concepts like the Catalan numbers along the way. Can you solve it before we reveal the answer? Let us know your approach in the comments! The Problem: Determine, with proof, all positive integers k such that the expression (1/(n+1)) * Σ [i=0 to n] (n choose i)^k is an integer for every positive integer n. 00:00 - The Problem Statement (USAMO) 00:28 - Step 1: Testing the Waters with k = 1 01:22 - Step 2: Finding a Necessary Condition (k must be even) 02:38 - Step 3: Proving All Odd Integers Fail (Using Modular Arithmetic) 04:17 - Step 4: Proving All Even Integers Work 04:28 - The k=2 Case and the Catalan Numbers 04:53 - The General Proof for Even k (Using Lucas's Theorem) 06:41 - Final Conclusion & Summary of the Proof Subscribe for more elegant proofs of challenging math olympiad problems! #NumberTheory #USAMO #MathOlympiad #Combinatorics #Proof