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Q1. A students measured the diameter of a small steel ball using a screw gauge of least count 0.001cm. The main scale reading is 5mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is (NEET -2018) a) 0.053cm b) 0.525cm c) 0.521cm d) 0.529cm Q2. Calculate the mean percentage error in five observations, 80.0, 80.5,81.0,81.5 and 82.0 ( AIIMS-2019) a) 0.74% b)1.74% c) 0.38% d) 1.38% Q3. The main scale of vernier callipers has n divisions /cm. n divisions of the vernier scale coincide with n-1 divisions of main scale. The least count of the vernier callipers is ( NEET-2019) Q6. The angle of 1 (minute of arc) in radian is nearly equal to (NEET-2020) (a) 1.75 × 10–2 rad (b) 2.91 × 10–4 rad (c) 4.85 × 10–4 rad (d) 4.80 × 10–6 rad Q7. Taking into account of significant figures, what is the value of 9.99m – 0.0099m? (NEET 2020) a) 9.98m b) 9.980m c) 9.9m d) 9.9801m Q8. A screw gauge has lease count of 0.01mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is (NEET 2020) a) 0.25mm b)0.5mm c) 1.0mm d) 0.01mm Q9. If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy. (NEET-2021) a) [F][A][T 2 ] b). [F][A][T −1 ] c) [F][A −1 ][T] d) [F][A][T] Please see the complete video The videos will contain the content as per the CBSE board. The content will also help to those students who are going to appear in NEET or JEE Exams.