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Discover the nuances of pointer copying in C programming with our in-depth guide. Learn how to avoid unintended modifications in your data structures while building a compiler. --- This video is based on the question https://stackoverflow.com/q/69902866/ asked by the user 'e god' ( https://stackoverflow.com/u/15170833/ ) and on the answer https://stackoverflow.com/a/69903087/ provided by the user 'Barmar' ( https://stackoverflow.com/u/1491895/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions. Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: C Pointer Copying Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l... The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license. If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com. --- Understanding C Pointer Copying: A Guide for Compiler Developers When diving into C programming, one aspect that can often confuse developers—especially those working on complex projects such as compilers—is how pointers behave during copying and manipulation. In particular, a common question arises around why modifying a copied pointer can also inadvertently change the original one. This guide will address this issue, breaking down the solution into manageable sections to enhance your understanding. The Problem While working on a compiler, you might encounter a situation similar to the following code snippet: [[See Video to Reveal this Text or Code Snippet]] In this code, you might think that by creating a copy of e into ef, any subsequent modifications to ef should not affect e. However, when you run the code and notice that ef=ef->next also changes the address of e, it raises the question: why does this happen? Understanding Pointers To grasp this problem effectively, it’s vital to understand how pointers work in C: Pointers Store Addresses: A pointer variable holds the memory address of another variable (in our case, FRAME *e points to a FRAME structure). Copying Pointers: When you assign one pointer to another (e.g., FRAME *ef = e;), you're copying the address. Both pointers (ef and e) now reference the same memory location. Modifying the Address: If you change the pointer ef to point to a different location with ef=ef->next;, you are not changing e, but after this operation, ef points to the next FRAME. The confusion comes from the manipulation of the contents that these pointers reference. The Solution To avoid such unintended consequences, it’s essential to manage how you handle pointers and their referenced data. The primary issue in the original code is that the bindings members of both e and ef are being modified directly, leading to changes that affect both pointers. Steps to Correct the Code Here’s how you can adjust the code to avoid altering the original pointer: Use a New Variable: Instead of modifying ef->bindings directly, create a temporary variable that references ef->bindings. Update Code Structure: Here’s the modified version of the function: [[See Video to Reveal this Text or Code Snippet]] Key Takeaways Some Common Misunderstandings: It’s easy to mistake pointer copying as creating a completely independent object. Both pointers still point to the same object in memory. Careful Manipulation: Always be cautious when manipulating data that multiple pointers reference. Using new temporary variables for traversal can help avoid unexpected changes in your data structures. Conclusion Managing pointers effectively is a crucial skill in C programming, especially for those tackling complex systems like compilers. By understanding how copying works and the implications of modifying referenced data, you can write safer and more robust code. If you're faced with similar scenarios in your projects, remember the importance of using temporary variables to protect original data structures.