🔥 LeetCode 110 | Balanced Binary Tree (08-02-2026) | Easy Explanation скачать в хорошем качестве

🔥 LeetCode 110 | Balanced Binary Tree (08-02-2026) | Easy Explanation

In this problem, you are given the root of a binary tree, and your task is to check whether the tree is height-balanced or not. A binary tree is called balanced if, for every node, the height difference between its left and right subtrees is at most 1. 🧠 Main Idea The key idea is to calculate the height of each subtree and make sure the difference never becomes greater than 1. If at any point the difference is more than 1, the tree is not balanced. So, we need to: ✔ Find the height ✔ Compare left and right subtrees ✔ Detect imbalance early ⚙️ Approach Explained This problem is best solved using recursion with postorder traversal: 🔹 First, check left subtree 🔹 Then, check right subtree 🔹 Calculate height 🔹 Verify balance condition By doing everything in one traversal, we get an efficient O(n) solution. 📌 Key Concepts Covered Binary Trees Recursion Tree Height Depth-First Search (DFS) 💡 Why Solve This Problem? LeetCode 110 is a perfect problem to strengthen your understanding of tree traversal and recursion. It is commonly asked in interviews and helps you build a strong foundation in tree-based problems. 👍 Like 👍 | Share 🔁 | Subscribe 🔔 for more LeetCode explanations and easy coding tutorials. 💬 Comment if you want the Java or Python solution. Happy Coding! 💻🔥