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Single Number II | Find the Unique Element Appearing Once | Optimized Approach

Practise Link: https://leetcode.com/problems/single-... Medium Link:   / finding-the-unique-number-in-a-set-where-e...   In this video, I explain how to find the unique element in an array where every element appears exactly three times except for one element that appears once. I cover three different approaches, from brute force to an optimal bitwise manipulation method. Approaches Explained: 1️⃣ Brute Force (Two Nested Loops) - O(n²) Check every element’s frequency manually using nested loops. Simple but highly inefficient for large inputs. 2️⃣ HashMap (Frequency Counting) - O(n) Time, O(n) Space Use a HashMap to store the count of each number. Iterate through the array to find the unique element. 3️⃣ Bitwise Manipulation (Optimal Solution) - O(n) Time, O(1) Space Utilize bitwise operations to count bits across all numbers. Extract the unique number appearing once while others appear thrice. Timelines: ⏳ Intro: 0:00 ⚡ Approach 1 (Brute Force): 01:20 🛠 Approach 2 (HashMap): 03:34 🚀 Approach 3 (Bitwise Manipulation - Best Approach): 07:48 This approach is simple, efficient, and widely used in competitive programming and interviews! 🚀 💡 Watch the full explanation and try implementing it yourself! 👉 Question for You: What other algorithms would you like me to cover? Let me know in the comments! Whether you're just starting with DSA or preparing for coding interviews, this video will guide you through various methods to tackle array problems efficiently. Don’t forget to check out our full LeetCode DSA series here for more problem-solving insights! DSA Problems Playlist:    • DSA Problems   Whether you're prepping for coding interviews or improving problem-solving skills, understanding array manipulation techniques like these can be crucial. 👉 Be sure to like, share, and subscribe for more Java tutorials, coding tips, and in-depth explanations!