Design Of One Way Slab As per IS: 456-2000 With Detailing | step by step скачать в хорошем качестве

Design Of One Way Slab As per IS: 456-2000 With Detailing | step by step

DESIGN OF ONE WAY SLAB AS PER IS:456-2000 WITH DETAILING STEP BY STEP #DESIGN #ONEWAYSLAB #CIVILPOSITIVE Design of One way slab Handwriting Notes Step by Step Link:- https://drive.google.com/file/d/1aoKe... Detailing Requirements of Reinforced Concrete Slab as per IS456: 2000 a) Nominal Cover: For Mild exposure – 20 mm For Moderate exposure – 30 mm However, if the diameter of bar do not exceed 12 mm, or cover may be reduced by 5 mm. Thus for main reinforcement up to 12 mm diameter bar and for mild exposure, the nominal cover is 15 mm. b) Minimum reinforcement: The reinforcement in either direction in slab shall not be less than 0.15% of the total cross sectional area for Fe-250 steel 0.12% of the total cross-sectional area for Fe-415 & Fe-500 steel. c) Spacing of bars: The maximum spacing of bars shall not exceed Main Steel – 3d or 300 mm whichever is smaller Distribution steel –5d or 450 mm whichever is smaller Where, ‘d’ is the effective depth of slab. Note: The minimum clear spacing of bars is not kept less than 75 mm (Preferably 100 mm) though code do not recommend any value. d) Maximum diameter of bar: The maximum diameter of bar in slab, shall not exceed D/8, where D is the total thickness of slab. Procedure Steps for One Way Slab in the below section. Design of One way slab 1.Based on the stiffness requirement assume suitable depth and calculate the effective span 2.Calculate the loads acting on the slab. 3.Calculate factored moment and shear force by considering the one-meter width of the slab  For simply supported slab  Factored moment =Mu= Wu× l²/ 8 Shear Force = Vu = Wu×l / 2 4.Determine the minimum depth required to resist bending moment by equating  Mu= Mulim = k×fck×bd² b=1000mm k=0.138 For Fe 415 steel and  k=0.148 for mild steel  The depth provided should be more than this value 5.Determine the area of steel considering meter width of the slab. 6.Determine the spacing of bars by using    S= ast/Ast ×1000   ast – area of bar used   Ast- total area of steel required    Spacing should be more than 3d or 300mm whichever is less 7.Distribution steel provides minimum reinforcement as distribution steel at a spacing of 5d or 450mm whichever is less. 8.Slab is checked for deflection shear and development length.In case of slabs( thin members), no need of even minimum shear reinforcement.Shear due to loads always must be less than the shear strength of concrete. Categoes Building Materials  Concrete Technology  Construction Management  Enviornmental Engineering Lab  Fluid Mechanics  Gate Notes and PDF  General  Geotechnical Engineering  Guest Posts  Latest Construction TECHNOLOGY Mechanics of solids  Rate Analysis and Estimation  Seminar & Projects  Structural Analysis  Surveying  Testes on Cement Testes on Fresh Concrete  Tests on Aggregates  Tests on Hardened Concrete Traffic Engineering  Transportation Engineering  Transportation Engineering Lab  Uncategorized  Waste Water Engineering  Water resource engineering  Water Supply Engineering