leet code 868 Binary Gap|daily coding скачать в хорошем качестве

leet code 868 Binary Gap|daily coding

*Binary Gap Problem Explained | Step-by-Step with Example | Java Solution* In this video, we explore the *Binary Gap* problem — a popular coding interview and DSA question that helps you understand *bit manipulation* and binary traversal. --- 📌 *Problem Statement* Given a positive integer `n`, convert it into its binary representation and find the **maximum distance between two consecutive `1`s**. This distance is called the **Binary Gap**. --- 📊 *Example:* Input: `n = 22` Binary Representation: `10110` Now measure the distance between consecutive `1`s: `1 → 0 → 1` → distance = 2 `1 → 1` → distance = 1 ✅ *Maximum Distance = 2* So, the Binary Gap of 22 is **2**. --- 💡 *What You’ll Learn in This Video* ✔ How to convert a number to binary using logic (no built-in conversion) ✔ How to traverse bits using division and modulus ✔ How to track distances between `1`s efficiently ✔ Step-by-step dry run with table explanation ✔ Clean and optimized Java implementation ✔ Time & Space Complexity analysis --- 🧠 *Why This Problem is Important* This question strengthens your understanding of: Bitwise operations Logical thinking in binary systems Efficient looping without extra space Interview-ready problem-solving approach --- 👩‍💻 *Approach Used* We scan the number bit-by-bit from right to left: 1️⃣ Find the first `1` 2️⃣ Start counting distance 3️⃣ When next `1` appears → update maximum gap 4️⃣ Continue until the number becomes zero --- 🚀 Perfect for: • Beginners learning DSA • Students preparing for coding interviews • Anyone who wants to master binary logic --- 📥 Try it yourself and comment your answer for another number! 🔔 Don’t forget to Like, Share & Subscribe for more DSA explanations. #BinaryGap #DSA #JavaProgramming #CodingInterview #BitManipulation #LearnToCode #GeekStreak #ProblemSolving