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In this video, we solve LeetCode 712. Minimum ASCII Delete Sum for Two Strings using a clean Dynamic Programming approach. The key idea is to think in terms of cost, not just matching characters: If characters match, we keep them with zero cost If they don’t, we delete one character and pay its ASCII value Instead of directly finding the common string, we compute the minimum total ASCII cost required to make both strings equal. We define a DP state where: dp[i][j] represents the minimum delete cost to make s1[0..i] and s2[0..j] equal Base cases handle deleting all remaining characters from one string and we use prefix sums to handle this efficiently Transitions choose the cheaper deletion when characters differ This leads to an optimal O(n × m) solution. This problem is part of today’s LeetCode Daily Problem of the Day (POTD). 🔹 What you’ll learn: • How to model string problems as cost minimization • Why ASCII values naturally define deletion cost • How base cases simplify edge conditions • Top-down DP with memoization 🔹 Topics: • Dynamic Programming • String DP • Memoization • Prefix Sums Clear problem explanation, intuition-first walkthrough, and clean Java implementation. Problem link - https://leetcode.com/problems/minimum... Java Code - https://pastebin.com/QG6zFLTH Python Code - https://pastebin.com/6rfa1fen Time complexity - O(N*M) Space Complexity - O(N*M) Page Marker Extension - https://chromewebstore.google.com/det... Video Chapters - 00:00 - Problem Statement 02:35 - Approach 12:29 - Code 24:27 - Time and Space Complexity Leetcode daily playlist - • LeetCode Daily Problems LeetCode Easy POTD playlist - • LeetCode Easy LeetCode Medium POTD playlist - • LeetCode Medium LeetCode Hard POTD playlist - • LeetCode Hard If you want to practice daily and improve your problem-solving skills, this is the place to follow along. #leetcode #dsa #dp #memoization #prefixsum #strings #dynamicprogramming #leetcodeproblemoftheday #algorithm #java #python #code #leetcodechallenge #codinginterview #problemsolving