Q.6 NEET 2026: Solve Ladder Problems in 30 Seconds! 🪜 | Rotational Mechanics : NEET 2025 NUMERICAL скачать в хорошем качестве

Q.6 NEET 2026: Solve Ladder Problems in 30 Seconds! 🪜 | Rotational Mechanics : NEET 2025 NUMERICAL

Stop wasting 10 minutes on a single Equilibrium question! The Ladder Problem is a favorite for NEET examiners because it combines Gemini said The ladder problem is a classic application of Static Equilibrium, where an object (the ladder) remains at rest because all the forces and torques acting on it perfectly cancel each other out. To solve this for NEET-style questions, we break the problem into three specific conditions. 1. Translational Equilibrium For the ladder to not slide up, down, left, or right, the net force in every direction must be zero. Vertical Forces (∑F y ​ =0) The upward forces must equal the downward forces. Usually: Upward: Normal reaction from the floor (N f ​ ). Downward: Weight of the ladder (W=mg) and potentially the weight of a person climbing it. Equation: N f ​ =mg Horizontal Forces (∑F x ​ =0) The forces pushing the ladder toward the wall must equal the forces pushing it away. Toward the wall: Friction force (f) acting at the base. Away from the wall: Normal reaction from the wall (N w ​ ). Equation: f=N w ​ 2. Rotational Equilibrium For the ladder not to rotate (tip over), the sum of all torques (moments) about any point must be zero. ∑τ=0 (Clockwise Moments = Anticlockwise Moments) It is usually easiest to calculate moments about the base of the ladder because the torque from friction and the floor's normal force becomes zero (since the distance is zero). Clockwise Moment: Created by the weight (mg) acting at the center of gravity. Anticlockwise Moment: Created by the normal force of the wall (N w ​ ) pushing against the top. The Math: If L is the length and θ is the angle with the floor: mg⋅( 2 L ​ cosθ)=N w ​ ⋅(Lsinθ) 3. Calculating the Friction Force In NEET 2025 numericals, you are often asked for the minimum friction required to keep the ladder from slipping. Find N w ​ using the torque equation: N w ​ = 2 mgcotθ ​ Substitute N w ​ into the horizontal force equation: f=N w ​ = 2tanθ mg ​ Important Note: Friction is also defined as f≤μN f ​ . Therefore, to find the minimum coefficient of friction (μ): μ≥ 2tanθ 1 ​ Torque, Friction, and Normal Force. #NEETPhysics #RotationalMotion #PhysicsTricks #NEET2026 #PhysicsConcepts #AngularMomentum #MedicalEntrance #JEE #jeeaprilattempt #jeejanuaryattempt #jeeadvanced #mhtcetlatestupdates #kcet #rotationalmotion #education #physicstricks #SHORTCUTSINPHYSICS #physics #ncertsolutions #ncertphysics #neetncert#2025 Rank Saver #📉: Don't let tough Physics kill your rank again. •#2. @600# Elite Questions 🎯: Master 600 models; cover 100% concepts. •3. @#Target 150+ Marks 🏆: Lock in your score with surgical precision. •4. @#2-Hour Daily Limit ⏳: Max results in minimum time—save energy for Bio. •5. @#40-Day Masterplan 🗓️: 15 numericals a day to finish the entire syllabus. •6. @#Concept Clarity 💡: We teach the "Why," not just the solution. •7. @#Live Doubt Marathons 🏃‍♂️: Weekly live sessions to clear every hurdle. •8. @#5 Full PCB Mock Tests 📝: Realistic 720-mark practice for exam grit. •9. @#Darna Mana Hai 🛡️: Zero stress. One platform. Total confidence. 10. @#Just ₹2500 💎: Premium coaching at the best price. Watch demos now!