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Seekh Raha Hoon Youtube Channel #seekhrahahoon #coreldraw #diagramtutorial Three equal circles, each of radius 6cm, touch one another as shown in the figure. Find the area enclosed between them. [Take π = 3.14 and √3 = 1.732.] Join ABC. Since, all sides of Δ ABC are equal (radius is 6cm), therefore, ΔABC is an equilateral triangle. Now, to find the shaded area, we have to subtract the area of the three sectors so formed from the area of the equilateral triangle ΔABC.Therefore, Area of the equilateral triangle Follow & Contact With Us Facebook : https://www.facebook.com/profile.php?... WhatsApp : whatsapp.com/channel/0029Va5gUwtL2ATpUAuMr30s Instagram : / seekhrahahoon Twitter : / seekhraha_hoon Telegram : https://t.me/+7VDaSTTNjHIxNDU1 Related searches if three circles of radius a each are drawn such that three equal circles, each of radius 2cm touch one another then the area enclosed in between them is three equal circles, each of radius 2 cm touch one another find the area enclosed in between them four equal circles, each of radius a, touch each other three circles of equal radius 'a' cm touch each other the area of the shaded region is three equal circles of radius 3 cm touch one another in outside find the area enclosed by them four equal circles, each of radius 5 cm four equal circles each of radius 3.5 cm touch one ........................................................................ Copyright Disclaimer under section 107 of the Copyright Act 1976, allowance is made for “fair use” for purposes such as criticism, comment, news reporting, teaching, scholarship, education and research. Fair use is a use permitted by copyright statute that might otherwise be infringing.