LeetCode 35 Explained | Search Insert Position in Java (Binary Search Made Simple) скачать в хорошем качестве

LeetCode 35 Explained | Search Insert Position in Java (Binary Search Made Simple)

In this video, we solve *LeetCode 35 – Search Insert Position* using an efficient *Binary Search* approach in **Java**. The goal of this problem is simple: Given a sorted array of integers, either *find the target value* or *determine the correct index where it should be inserted* to keep the array sorted. 🔍 Intuition Because the array is already sorted, scanning linearly would be inefficient. Binary Search allows us to **cut the search space in half at every step**, making it the perfect tool for this problem. 🛠️ Approach Use two pointers: `start` and `end` Repeatedly compute the middle index Compare the middle value with the target: Move right if the target is larger Move left if the target is smaller If the target is found, return its index If not found, return the `start` pointer — this represents the correct insertion position ⏱️ Time & Space Complexity *Time Complexity:* `O(log n)` *Space Complexity:* `O(1)` (iterative solution, no extra memory) 💡 Why This Solution Works Binary Search guarantees efficiency and correctness because: The array is sorted The insertion index naturally emerges once the search window collapses This pattern appears **frequently in coding interviews**, so mastering it is a must 🚀 👉 Don’t forget to like, subscribe, and check out my other LeetCode walkthroughs in Java! Follow me on my socials to connect and see more awesome stuff 📌 *GitHub:* [https://github.com/NganeEmmanue](https://github.com/NganeEmmanue) 💼 *LinkedIn:* [  / ngane-emmanuel-b25242150  ](  / ngane-emmanuel-b25242150  ) 📸 *Instagram:* @nganeemmanuel