#redox скачать в хорошем качестве

#redox

This video discusses how to correctly calculate the oxidation states of elements in chemical compounds, especially when traditional methods lead to incorrect results. The presenter highlights cases where a "peroxo bond" (O-O linkage) is present, which causes the oxidation state of oxygen to be -1 instead of the usual -2. The video explains this concept through three examples: • H2SO5 (Caro's Acid) (0:07-6:30): • The traditional calculation gives a sulfur oxidation state of +8 (2:39), which is incorrect because sulfur's maximum oxidation state is +6 (2:59). • The correct calculation, considering the peroxo bond, yields an oxidation state of +6 for sulfur (4:25, 4:42). • The video also touches on the acidic nature of H2SO5, noting that the second hydrogen is not easily lost due to intramolecular hydrogen bonding (5:41-6:20). • CrO5 (Chromium Peroxide) (6:32-9:22): • The traditional method would lead to a +10 oxidation state for chromium (7:40), which is impossible as chromium's maximum is +6 (8:05). • The unique "butterfly structure" of CrO5 contains two peroxo linkages (7:16, 8:56). • Correct calculation based on the structure shows the chromium oxidation state is +6 (9:17). • K3CrO8 (9:32-12:20): • This is presented as a frequently doubted example (9:35). A simple calculation might suggest +13 (10:48), which is incorrect as chromium's maximum is +6 (10:53). • The structure of K3CrO8 contains four peroxo linkages (11:12). • The correct oxidation state for chromium in this compound is determined to be +5 (11:32, 12:16). The video concludes by emphasizing that the traditional "x-method" of calculating oxidation states fails when a compound contains an O-O linkage or peroxo bond (5:03-5:12, 8:56-9:05).