Uniform Circular Motion (UCM) - Motion | Class 9 Physics скачать в хорошем качестве

Uniform Circular Motion (UCM) - Motion | Class 9 Physics

👉Previous Video:    • Equations of Motion : NCERT Questions (Par...   👉Next Video:    • Motion - NCERT Exercises | Class 9 Physics   ✔️📚👉 Watch Full Free Course:- https://www.magnetbrains.com​ ✔️📚👉 Get Notes Here: https://www.pabbly.com/out/magnet-bra... ✔️📚👉 Get All Subjects playlists:- ​https://www.pabbly.com/out/all-videos... ✔️📚👉 Student Feedback Form: https://pabbly.com/out/feedbackform =============================================== 📢Full Playlist Link:   • Class 9 Physics (New Session 2023-24) | Co...   ✅ In this video, ✔️ Class: 9 ✔️ Subject: Physics ✔️ Chapter: Motion ✔️ Topic Name: Equations of Motion : NCERT Questions (Part 1) =============================================== 00:00 introdction 02:36 Uniform Circular motion 3:13 Example 1 7:36 Uniform Circular motion 10:06 Example 2 12:34 Numericals Questions 1 14:59 Question 2 17:13 Website Overview =============================================== 📢 🔥 Available (Kindergarten to 12th) all Video Subject wise Playlist https://www.pabbly.com/out/all-videos... Why study from Magnet Brains? Magnet Brains is an online education platform that helps give You NCERT/CBSE curriculum based free full courses from Kindergarten to Class 12th so that you can perform well in any and all exams you give in your academic career. 👉Contact us 🤑🤑 ➡️ Connect with us : [email protected] ➡️ Website : https://www.magnetbrains.com/ ➡️ Subscribe to us on YouTube:    / @magnetbrainseducation   ➡️ Subscribe to Magnet Brains Hindi Medium :    / @magnetbrainshindimedium   ➡️ Facebook : https://pabbly.com/out/facebook ➡️ Instagram : https://pabbly.com/out/instagram ➡️ Telegram : http://pabbly.com/out/telegram Points covered in this video:- Example 8.5 A train starting from rest attains a velocity of 72 km h–1 in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity. Solution: We have been given u = 0; v =72 km h-1 = 20 ms-1 and t = 5 minutes = 300 s (i) From Eq. (8.5) we know that, Example 8.6 A car accelerates uniformly from 18 km h–1 to 36 km h–1 in 5 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time. Solution: We are given that. u = 18 km h-1 = 5 ms-1 v = 36 km h-1 = 10 ms-1 t = 5s (i) From Eq. (8.5) we have, . Disclaimer: "This video is for educational and informational purposes only and is not intended to infringe on any copyrights. If you believe that this video has used any copyrighted material in a way that constitutes copyright infringement, please contact us at [email protected] and we will take appropriate action."