How to find the percent composition of Sr(H2PO4)2 (Strontium Dihydrogen Phosphate) скачать в хорошем качестве

How to find the percent composition of Sr(H2PO4)2 (Strontium Dihydrogen Phosphate)

To calculate the percent composition of Sr(H2PO4)2 (Strontium Dihydrogen Phosphate), follow these steps: ``` 1. Determine the atomic masses of each element: Strontium (Sr): 87.62 g/mol Hydrogen (H): 1.008 g/mol Phosphorus (P): 30.97 g/mol Oxygen (O): 16.00 g/mol 2. Calculate the molar mass of Sr(H2PO4)2: Strontium (Sr): 1 × 87.62 g/mol = 87.62 g/mol Hydrogen (H): 2 × 2 × 1.008 g/mol = 4.032 g/mol (because there are 2 H2 groups) Phosphorus (P): 2 × 30.97 g/mol = 61.94 g/mol Oxygen (O): 8 × 16.00 g/mol = 128.00 g/mol (because there are 8 oxygen atoms) 3. Total molar mass of Sr(H2PO4)2: 87.62 g/mol (Sr) + 4.032 g/mol (H) + 61.94 g/mol (P) + 128.00 g/mol (O) = 281.59 g/mol 4. Calculate the percent composition by mass for each element: Percent of Sr = (87.62 g/mol ÷ 281.59 g/mol) × 100 = 31.11% Percent of H = (4.032 g/mol ÷ 281.59 g/mol) × 100 = 1.43% Percent of P = (61.94 g/mol ÷ 281.59 g/mol) × 100 = 22.01% Percent of O = (128.00 g/mol ÷ 281.59 g/mol) × 100 = 45.45% Result: Percent composition of Sr(H2PO4)2: Strontium (Sr): 31.11% Hydrogen (H): 1.43% Phosphorus (P): 22.01% Oxygen (O): 45.45% ```