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IIT-JEE 2006 Differentiability PYQ | Graph Based Concept In this video, we solve a very interesting IIT-JEE 2006 Mathematics PYQ based on Differentiability and Graph Concept. This problem shows how graph analysis helps in understanding continuity and differentiability. Question: If f(x) = min {1, x², x³} Then determine which of the following statements are correct: (A) f(x) is continuous everywhere (B) f(x) is continuous and differentiable everywhere (C) f(x) is not differentiable at two points (D) f(x) is not differentiable at one point This type of conceptual PYQ frequently appears in JEE Advanced, where graph interpretation plays a crucial role in determining differentiability. Students preparing for IIT-JEE / JEE Advanced Mathematics should understand this concept clearly because similar ideas appear in Limits, Continuity and Differentiability problems. 🔥 Key Concepts Covered • Graph of min functions • Continuity and differentiability • Graph based approach in calculus • IIT-JEE PYQ solving techniques If you like the content, Subscribe for more JEE Advanced PYQs and powerful concepts in Mathematics.