LeetCode 3825 — Longest Strictly Increasing Subsequence With Non-Zero Bitwise AND скачать в хорошем качестве

LeetCode 3825 — Longest Strictly Increasing Subsequence With Non-Zero Bitwise AND

LeetCode 3825 — Longest Strictly Increasing Subsequence With Non-Zero Bitwise AND From Biweekly Contest 175 Problem Summary: You are given an array nums. You must find the length of the longest strictly increasing subsequence whose bitwise AND of all elements is non-zero. If no such subsequence exists, return 0. Example: [5,4,7] → answer = 2 because subsequence [5,7] has AND = 5 (non-zero) Why this problem is tricky: It looks like a normal LIS problem… but with an extra bitwise constraint. Brute force and DP explode quickly and cause TLE. Key Insight: For AND to stay non-zero, at least one bit must remain 1 across all chosen elements. So we flip the thinking: Instead of choosing subsequences directly, we choose a bit that must survive. Strategy: For each bit position (0 → 31): 1. Filter numbers that contain that bit 2. Run Longest Increasing Subsequence (LIS) 3. Take the maximum LIS length This converts exponential search into an efficient O(32 × n log n) solution. Concepts used: ✔ Bit manipulation ✔ Longest Increasing Subsequence ✔ Greedy optimization ✔ Contest strategy thinking ✔ Pattern recognition This is a perfect interview question combining LIS + bit tricks + optimization insight. Java implementation explained step-by-step in the video. Subscribe for daily contest breakdowns and interview hacks: DSA | Java | LeetCode | Competitive Programming #leetcode3825 #biweekly175 #coding #dsa #java #lis #bitmanipulation #shorts #leetcode3825 #biweekly175 #leetcodecontest #coding #dsa #java #lis #bitmanipulation #shorts #coding #codinghelp