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Discover how to properly bind a model to a URL action in the success section of an AJAX call in ASP.NET Core. Learn with practical code examples! --- This video is based on the question https://stackoverflow.com/q/74333576/ asked by the user 'NedaM' ( https://stackoverflow.com/u/14617081/ ) and on the answer https://stackoverflow.com/a/74342171/ provided by the user 'Xinran Shen' ( https://stackoverflow.com/u/17438579/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions. Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to bind a model to URL Action in success ajax call section? Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l... The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license. If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com. --- How to Bind a Model to URL Action in a Success AJAX Call with ASP.NET Core When working with AJAX calls in ASP.NET Core, you may encounter situations where you need to redirect to another page with data (e.g., a model) after a successful operation. However, JavaScript's window.location.href is often misused to perform this action. What’s more, it cannot send a POST request but rather only performs a GET request, which can lead to errors and unexpected behavior. In this guide, we’ll explore the correct way to handle this scenario and provide a clear solution. Understanding the Problem In your form, you want to filter orders using a model that is sent as part of an AJAX call. The challenge arises when trying to redirect to another action (ShowList) with the results returned from the Filter action after a successful AJAX call. The decision to use window.location.href for this redirection is where things can go wrong, resulting in errors such as an HTTP 500 internal server error. Example Code Structure Here’s the code structure you originally had: [[See Video to Reveal this Text or Code Snippet]] The Solution To resolve this problem, we need to implement a strategy that allows you to stay within AJAX's capabilities while also correctly redirecting after a successful operation. Instead of trying to redirect directly in the success section of the first AJAX call, you'll send another AJAX request to load data from the ShowList action. Here's how you can structure your AJAX call: Step 1: Update the Filter Function You will modify the FilterOrder function like this: [[See Video to Reveal this Text or Code Snippet]] Key Changes Explained Separate AJAX Request: After a successful filter AJAX call, we send a second AJAX request to ShowList. This allows us to use POST for both requests while also maintaining the data flow. Dynamic HTML Injection: The response from ShowList is injected into a designated <div> (e.g., listContainer). This might be a section of your page where you want to display the results. Modal Management (Optional): If you're using a modal to present data, this approach allows you to close or manipulate it seamlessly based on user actions. Final Thoughts By following this approach, you're not only resolving the HTTP method restriction but also making your application more modular and maintainable. Handling server responses and DOM manipulations via AJAX means a smoother user experience without unnecessary page reloads. Implementing AJAX correctly is crucial in modern web applications, especially with frameworks like ASP.NET Core that leverage these capabilities to offer rich, dynamic interactions. Now you know the proper way to bind your model to a URL action after a successful AJAX call—happy coding!