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Differential Amplifier Part 3

Analog IC Design | Differential Pair Insight Spent time revisiting the MOS differential amplifier and deriving the core relationship between input differential voltage and drain current difference. Starting from large-signal MOS equations and current steering in a symmetric differential pair, we arrive at a key result: ➡️ The difference in drain currents is a function of the input differential voltage, device parameters, and bias current. This derivation builds strong intuition on: (I_D1 − I_D2) = (1/2) μ_n C_ox (W/L) (V_in1 − V_in2) √[ (4 I_SS) / (μ_n C_ox (W/L)) − (V_in1 − V_in2)^2 ] Current redistribution in differential pairs Large-signal vs small-signal behavior Why differential pairs are fundamental to op-amps, comparators, and analog front-ends 📌 A solid reminder that good analog design starts from first principles, not just simulation. Always rewarding to connect math with circuit behavior. hashtag#AnalogICDesign hashtag#VLSI hashtag#CMOS hashtag#DifferentialAmplifier hashtag#ElectronicsEngineering hashtag#AnalogCircuits hashtag#LearningByDerivation