JEE Mains 2026 Maths | 22 Jan Shift 1 | Memory Based Questions & Solutions | Full Paper Analysis скачать в хорошем качестве

JEE Mains 2026 Maths | 22 Jan Shift 1 | Memory Based Questions & Solutions | Full Paper Analysis

JEE Mains 2026 – 22 January Shift 1 Maths In this video, we discuss memory based questions asked in JEE Main 2026 (22 January Shift 1) with complete step by step solutions. This session includes questions from Arithmetic Progression, Binomial Theorem, Matrices, Functions, Inverse Trigonometry, Relations, Differential Equations, Modulus, Definite Integrals, Probability, Area Under Curves, and Probability Distribution. This video will help you: Verify memory based questions Check concepts asked in the exam Understand the difficulty level of the paper Revise high weightage chapters Ideal for JEE Main 2026 aspirants who want quick revision and exam level clarity. 00:00:00 If the sum of the first four terms of an arithmetic progression is six, and the sum of the first six terms of the same arithmetic progression is four, find the sum of the first twelve terms of that arithmetic progression. 00:06:43 Find the coefficient of x power 48 in the expansion of 1(1 + x) + 2(1 + x)^2 + 3(1 + x)^3 + … + 100(1 + x)^100. 00:13:28 If A = [ 2 3 ] [ 3 5 ] then find the value of modulus of (A power 2025 minus 3A power 2024 plus A power 2023). 00:00:00 If the sum of the first four terms of an arithmetic progression is six, and the sum of the first six terms of the same arithmetic progression is four, find the sum of the first twelve terms of that arithmetic progression. 00:06:43 Find the coefficient of x power 48 in the expansion of 1(1 + x) + 2(1 + x)^2 + 3(1 + x)^3 + … + 100(1 + x)^100. 00:13:28 If A = [2 3; 3 5], then find the value of modulus of (A power 2025 minus 3A power 2024 plus A power 2023). 00:42:50 The solution of the differential equation x dy minus y dx equals square root of (x square + y square) dx is, where c is the constant of integration. 00:46:08 The number of real solutions of the equation x multiplied by |x + 4| plus 3 multiplied by |x + 2| plus 10 equals 0 is. 00:53:02 Find the value of the definite integral from minus pi divided by 2 to pi divided by 2 of dx divided by ([x] + 4), where [x] denotes the greatest integer function. 00:56:43 If a line ax + y = 1 does not intersect the hyperbola x square minus 9y square equals 9, then a possible value of a is. 01:01:15 If the integral of (cos x) power minus 5 by 2 multiplied by (sin x) power minus 11 by 2 dx equals (p1 divided by q1)(cot x) power 9 by 2 plus (p2 divided by q2)(cot x) power 1 by 2 minus (p4 divided by q4)(cot x) power minus 3 by 2 plus c, where c is the constant of integration, then find the value of (15 multiplied by p1 p2 p3 p4) divided by (q1 q2 q3 q4). 01:14:16 Let 6 multiplied by the integral from 1 to x of f(t) dt equal 3x f(x) minus x cube plus 4. Find the value of f(2) minus f(3). 01:18:05 If the domain of the function 1 divided by ln(10 minus x) plus sin inverse of (x + 2) divided by (2x + 3) is (minus infinity, minus a] union (minus 1, b) union (b, c), then find the value of b plus c plus 3a. 01:28:11 If tan inverse of (4x) plus tan inverse of (6x) equals pi divided by 6, then the number of solutions in the interval (minus 1 divided by 2 square root 6, 1 divided by 2 square root 6) is. 01:37:04 Let M = {1, 2, 3, …, 16} and R be a relation on M defined by x R y if and only if 4y equals 5x minus 3. Then the number of ordered pairs required to be added in R to make it symmetric is. 01:19:15 Two numbers A and B are selected from the set {1, 2, 3, ..., 50}. Find the probability that AB is divisible by 3. 01:22:11 The ratio of the areas into which the line x equals minus 1 divides the region enclosed by 1 plus x square less than or equal to y less than or equal to 3 minus x is m divided by n. Find the value of m plus n. 01:32:48 If a probability distribution is given by x: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 and P(x): k, 2k square, 6k square, k square plus k, 3k, k, k, k, k, k square, then find the value of P(3 less than x less than or equal to 6).