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Reactivities of Halogens as Oxidizing Agents |Quick check 13.2 |Lecture 3 |Chapter 13 |FSC 1st YearChemistry by Imiiacademy This topic is very important as long and short questions for board exam. Quick Check 13.2 a) The F-F bond is weaker than Cl-Cl bond although fluorine is the most electronegative element. Explain. Ans: The atomic size of fluorine (F = 72 pm) is less than chlorine (CI = 99 pm). Due to the small size, there is significant electron-electron repulsion between the lone pairs on the fluorine atoms, which weakens the bond despite the high electronegativity of fluorine. b) Is the reaction between NaCl(aq) and F₂ gas possible? i) Give reason whether yes or no. ii) If yes, write the equation for this reaction. Ans: i) Fluorine (F2) is a stronger oxidizing agent than chlorine (Cl₂) because it has a higher standard electrode potential. This means fluorine can displace chlorine from its compounds. In this case, fluorine oxidizes chloride ions (Cl-) to chlorine gas (Cl₂), while itself being reduced to fluoride ions (F-). ii) F2(g) + 2NaCl(aq) → 2NaF (aq) + Cl2(g) After watching this lecture, you will clearly understand: 👉Why Fluorine is the strongest oxidizing agent? 👉How bond dissociation energy affects oxidizing power? 👉Why oxidizing decreases down the group? 👉Don't forget to like, share and subscribe my channel. Your Searches: relative reactivities of halogens halogens as oxidizing agents oxidizing power of halogens why fluorine is strongest oxidizing agent trend in oxidizing power of halogens fsc 1st year chemistry chapter 13 halogens chemistry lecture periodic trends chemistry fsc punjab board chemistry #imiiacademy #1styearchemistry #Halogens #OxidizingAgents #BondStrength #FScChemistry #Chapter13 #ChemistryConcepts #Periodic Trends #BoardExam #lecture3