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⚡ Capacitor Sizing – CEC Section 26-200 Complete Guide In this 50-minute full lesson, we break down Canadian Electrical Code (CEC) Section 26-200 to 26-222 and explain everything you need to know about capacitor installations for Red Seal 309A preparation and real field applications. ⸻ 🔹 What Do Capacitors Do in Power Systems? Capacitors are commonly used in industrial and commercial electrical systems for: ✔ Power factor correction ✔ Reducing reactive power (kVAR) ✔ Lowering line current ✔ Improving system efficiency ✔ Reducing utility penalties When power factor is low, current increases. When we correct power factor to unity (1.0), reactive power is reduced and the system becomes more efficient. ⸻ 📚 CEC Section 26-200 – Capacitors This section governs installation requirements for: • Capacitor feeders • Capacitor branch circuits • Capacitor banks • Motor circuit capacitors ⸻ 🔹 Rule 26-208 – Conductor Sizing The ampacity of capacitor feeder and branch circuit conductors shall be: \ge 135\% \text{ of rated capacitor current} After calculating capacitor current: • Go to Table 2 (Copper) • Table 4 (Aluminum) • Apply Rule 4-006 if under 100A (60°C column) ⸻ 🔹 Rule 26-210 – Overcurrent Protection OCPD must be: \le 250\% \text{ of capacitor rated current} Use Table 13 for standard breaker sizes. Capacitors are allowed higher OCPD because they are not overload-sensitive devices like motors. ⸻ 🔹 Rule 26-212 – Disconnecting Means Required: ✔ Disconnect in each ungrounded conductor ✔ Within sight and not more than 9 m ✔ Or lockable open ✔ Warning label required ✔ 5-minute discharge wait time ⸻ 🔹 Rule 26-214 – Disconnect Rating Disconnect must be rated: \ge 135\% \text{ of capacitor rated current} ⸻ ⸻ 🔎 PROBLEM 1 – Power Factor Correction to Unity Given: 240V Single phase 23A PF = 0.80 lagging ⸻ Step 1 – Apparent Power (S) S = VI S = 240 \times 23 = 5520 VA = 5.52 kVA ⸻ Step 2 – Real Power (P) P = S \times PF P = 5.52 \times 0.8 = 4.42 kW ⸻ Step 3 – Reactive Power (Q) Q = \sqrt{S^2 - P^2} Q = \sqrt{5.52^2 - 4.42^2} Q = 3.3 kVAR So capacitor required: Q_c = 3.3 kVAR ⸻ Step 4 – Capacitor Current I_c = \frac{Q}{V} I_c = \frac{3300}{240} = 13.75 A ⸻ Step 5 – Reactance X_c = \frac{V}{I} X_c = \frac{240}{13.75} = 17.45 \Omega ⸻ Step 6 – Capacitance X_c = \frac{1}{\omega C} \omega = 2\pi f = 377 C = \frac{1}{377 \times 17.45} C = 0.000150 F C = 150 \mu F ✅ Required capacitor: 3.3 kVAR or 150 μF ⸻ 🔎 PROBLEM 2 – 25 kVAR, 600V, Three Phase Capacitor Bank ⸻ Step 1 – Capacitor Current I = \frac{kVAR}{\sqrt{3}V} I = \frac{25000}{1.732 \times 600} I = 24 A ⸻ a) Conductor Size (Rule 26-208) 24 \times 1.35 = 32.4 A Apply Rule 4-006 (less than100A → 60°C column) From Table 2: No. 8 AWG copper = 40A ✅ Minimum conductor = #8 AWG Copper AC90 ⸻ b) OCPD (Rule 26-210) 24 \times 2.5 = 60 A Next standard breaker size: ✅ 60A breaker ⸻ c) Disconnect Rating (Rule 26-214) 24 \times 1.35 = 32.4 A Minimum standard disconnect above that: ✅ 30A is too small Must select 60A disconnect (cannot go below calculated load) Correct practical answer: ✔ Minimum safe disconnect = 60A ⸻ 🔎 PROBLEM 3 – Transformer Sizing Given: 12 kVAR 208V Three phase For a capacitor: kVA = kVAR So: 12 kVA Apply 135% safety factor (practical design): 12 \times 1.35 = 16.2 kVA Next standard size: 15 kVA → too small 20 kVA → acceptable ✅ Minimum recommended transformer size = 20 kVA ⸻ 🎯 What You Learn in This Video ✔ How to calculate capacitor kVAR ✔ How to convert to microfarads ✔ How to size conductors per Rule 26-208 ✔ How to size OCPD per Rule 26-210 ✔ How to size disconnect per Rule 26-214 ✔ How to size transformer for capacitor load ✔ Real Red Seal style calculations