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Welcome to our Python programming tutorial on how to create a Python program to check whether a given number is even or odd. This beginner-friendly video will guide you step-by-step through the process of writing a simple and efficient Python script to determine the parity of any input number. In this Python tutorial, we'll cover the fundamental concepts of conditional statements and basic arithmetic operations in Python. You'll learn how to use the modulo operator to identify even and odd numbers with ease. The program we create will be versatile and can be used to handle various numeric inputs, helping you build a strong foundation in Python programming. Key topics covered in this Python video tutorial: Introduction to Python programming basics Understanding if-else statements in Python Implementation of the modulo (%) operator Identifying even and odd numbers in Python Running the program with different numeric inputs Python program demonstration with practical examples Whether you're a complete beginner or an experienced programmer looking to brush up on your Python skills, this video is designed to cater to learners of all levels. By the end of this Python programming tutorial, you'll have a clear understanding of how to determine whether a number is even or odd using Python and be well-equipped to apply this knowledge to solve other programming challenges. If you find this video helpful, don't forget to give it a thumbs up and subscribe to our channel for more Python tutorials and programming content. Feel free to leave your questions and suggestions in the comments section below, and we'll be glad to assist you! Keywords: Python Program Even Odd Number, Check Even or Odd in Python, Python Programming Tutorial, Python Tutorial for Beginners, Python Even Odd Program, Python Modulo Operator, Python If Else Statement, Python Arithmetic Operations, Python Programming Basics, Learn Python, Python Programming Examples, Python Coding Exercises, Python Beginners Guide, Python Programming Practice, Python Tips and Tricks.