JEE Mains 2026 Physics Solution | 21st Jan Shift 2 | Rotation & Pulley Problem (Q37) скачать в хорошем качестве

JEE Mains 2026 Physics Solution | 21st Jan Shift 2 | Rotation & Pulley Problem (Q37)

In this video, we solve a challenging Rotational Dynamics problem from the JEE Mains 2026 paper (21st Jan, Shift 2). The question involves calculating the acceleration of blocks connected over a composite pulley made of a rim and rods. 📝 Question Discussed: The pulley shown in the figure is made using a thin rim and two rods of length equal to the diameter of the rim. The rim and each rod have a mass of M. Two blocks of mass of M and m are attached to two ends of a light string passing over the pulley, which is hinged to rotate freely in vertical plane about its center. The magnitudes of the acceleration experienced by the blocks is _____. (Assume no slipping of string on pulley). Options: 1. (M-m)g / (2M+m) 2. (M-m)g / (M+m) 3. (M-m)g / [(11/3)M + m] 4. (M-m)g / [(8/3)M + m] 💡 Key Concepts Covered: System of Particles and Rotational Motion Moment of Inertia of Composite Bodies (Rim + Rods) Torque and Angular Acceleration (τ = Iα) No-Slipping Condition (a = Rα) Solving Coupled Equations of Motion To solve this, we first determine the Moment of Inertia of the specialized pulley and then apply Newton's Laws for both translation and rotation. 👨‍🏫 About the Instructor: Explained by Kanak Yadav, a graduate of NITK Surathkal. Welcome to Physics Unlocked ⚛🔓 – your go-to destination for conceptual clarity in Physics for JEE Mains, JEE Advanced, and NEET. 🔔 Subscribe for more JEE 2026 Solutions: [Insert your Channel Link Here] #JEEMains2026 #PhysicsSolutions #RotationalMotion #MomentOfInertia #PhysicsUnlocked #JEEMainsPhysics #NITKSurathkal #KanakYadav #JEE2026 #21JanShift2