| Charging of a Capacitor RC Circuit | | physics guru | | CL Maurya Sir | скачать в хорошем качестве

| Charging of a Capacitor RC Circuit | | physics guru | | CL Maurya Sir |

Let us assume the capacitor is fully uncharged. When we push the switch, the capacitor is uncharged, hence no voltage developed across the capacitor, thus the capacitor will behave as short circuit. At that moment the charge just starts accumulation in the capacitor. The current through the circuit will only be limited by resistance R. Top × HOME BASICS POWER SYSTEM MACHINES ELECTRONICS MCQ VIDEOS GUEST POST Search for: Charging a Capacitor Whenever we connect an uncharged capacitor with a voltage source it is exponentially charged until the voltage developed across the capacitor becomes equal and opposite to voltage of the source. Let us connect one capacitor of capacitance C in series with a resistor of resistance R. We also connect this series combination of capacitor and resistor with a battery of voltage V through a push switch S. charging a capacitor Let us assume the capacitor is fully uncharged. When we push the switch, the capacitor is uncharged, hence no voltage developed across the capacitor, thus the capacitor will behave as short circuit. At that moment the charge just starts accumulation in the capacitor. The current through the circuit will only be limited by resistance R. You may also be interested on Transistor as a Switch Extrinsic Semiconductors Energy Stored in Capacitor Gallium Arsenide Semiconductor Avalanche Breakdown How to Test Capacitors? That initial current is V / R. Now slowly the voltage is being developed across the capacitor, and this developed voltage is in opposite of the polarity of the battery. As a result the current in the circuit gradually decreased. It will be gradually decreased to zero, when the voltage across the capacitor becomes equal and opposite of the voltage of battery. The voltage gradually increases across the capacitor during charging. Let us consider the rate of increase of voltage across the capacitor is dv/dt at any instant t. The current through the capacitor at that instant is i=c dv/dt. so students watch like share and subscribe this video. thanks.