LeetCode 3013 – Divide an Array Into Subarrays With Minimum Cost II (Java) | Hard скачать в хорошем качестве

LeetCode 3013 – Divide an Array Into Subarrays With Minimum Cost II (Java) | Hard

In this video, I solve LeetCode Daily Question 3013 using Java. This is the Hard version of the minimum cost subarrays problem. Problem Summary: Divide the array into k disjoint contiguous subarrays Cost of each subarray is its first element The difference between the starting index of the 2nd and kth subarray must be ≤ dist Goal: minimize total cost Approach: Sliding window with two TreeSets Maintain the smallest (k-1) elements inside the valid window Use TreeSet balancing to keep optimal candidates Track rolling sum efficiently Key Concepts Used: Sliding Window TreeSet (Balanced BST) Two-set technique (Top k-1 minimum elements) Greedy optimization Time Complexity: O(n log n) Space Complexity: O(n) Problem Link: https://leetcode.com/problems/divide-... Java Solution Code (GitHub): https://github.com/Amandf/LeetCode-So... Subscribe for daily LeetCode Java solutions #leetcode #leetcodedaily #java #hardproblem #dsajava #algorithms #codinginterview