حسابات صيدلانيه (3) تم شرح Sodium Chloride Equivalent . Isotonic solution of mixed contents скачать в хорошем качестве

حسابات صيدلانيه (3) تم شرح Sodium Chloride Equivalent . Isotonic solution of mixed contents

تم شرح Isotonic solution of mixed contents • In some prescriptions, HCPs direct us to make a solution isotonic by adding the proper amount of some substance other than the active ingredient or ingredients. • The relative tonic effect of two substances—that is, the quantity of one that is the equivalent in tonic effects to a given quantity of the other—may be calculated if the quantity of one having a certain effect in a specified quantity of solvent is divided by the quantity of the other having the same effect in the same quantity of solvent. Sodium Chloride Equivalent Step 1.0.20 03g=0.072 g of sodium chloride represented by chlorobutanol Example 1 Papuverine hydrachloride (m.w. 376) is a 2-ion electralyte, dissociating 80% in a given concentra- tion, Calculute its sodium chloride equivalent. Because papaverine hydrochloride is a 2-ion electrolyte, dissociating 80%, its i factor is 1.8. 58.5 1.8 = 0.156, or 0.16, unswer. 18 376 1.8 • So, 0.16 g Sodium chloride represent 1 g of papaverine hydrochloride. • Example 2 Calculate the sadium chloride equivalent for glyeerin, a nonelectrolyte a molecular weight of 922 Glycerin, lactor = 1.0 58.5 1.0 1.8 * 92 = 0.35, answer. • So, 0.35g of sodium chloride represent 1 g of glycerin. • Example 3 How many grams of sodium chloride shuuld be used in compoanding the following prescription? B Pilocarpine Nitrate 0.3 g Sodium Chloride 4.5 30 ml. Purified Water ad Make isoton. sol. Sig For the eye Step 1. 0.23 x 0.3 g = 0.069 g of sodium chloride represented by the pilocarpine nitrate Step 2. 30 x 0.009 = 0.270 g of sodium chloride in 30 ml of an isotonie sodium chloride solution Step 3. 0.270 g (from Step 2) - 0.069 g (from Step 1) 0.201 g of sodium chloride to be used, answer. • Example 4 Henw many gyanN of boric acll should be used in compounding the following prescriptium? Phenacaine Hydrochloride Chlorobutanol 1% Boric Acid Purified Water ad Make isoton. sol. 4.5. 60 Sig. One drop in each eye. The prescription calls for 0,6 g of pheracaine hydrochloride and 0.3 g of chlorobutanol. 1. 0.24 x0.3 g= 0.072 g of sodium chloride represented by chlorobutanol Total: og=0.120 g of sodium chloride represented by phenacaine hydrochloride 0.192 g of sodium chloride represented by both ingredients Step 2 60 x 0.009 = 0.340g of sodium chloride in 60 ml of an isotonic sodium chloride solution Step 3. 0.540 g (from Step 2) - 0.192 g (from Step 1) 0.348 g of sodium chloride required to make the solution isotonic But because the prescription calls for boric acid: Step 4. 0348 g + 0.52 (sodium chloride equivalent of boric acid) = 0.669 g of boric acid to be used, answer Using an Isotonic Sodium Chloride Solution to Prenare Other Isotonic Solutions Example • Determine the volume of purified water and 0.9% sodium chloride to make 20 ml of 1% w/v solution of hydromorphone hydrochloride (E = 0.22) ،