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Dive deep into the world of optics with our comprehensive video on Variable Refractive Index! 🌟 Perfect for students preparing for JEE, NEET, and Board exams, and teachers looking for clear explanations. In this video, we'll cover: What is Variable Refractive Index? Importance in real-life applications like mirages and optical fibres Solved numericals to solidify your understanding: Graded-Index Fibres Mirage Formation Refraction in Non-Uniform Mediums Graded-Index Lenses If you haven't watched previous videos here are the links • REFLECTION BY PLANE SURFACES | RAY OPTICS-... • REFLECTION BY SPHERICAL MIRRORS | RAY OPTI... • REFRACTION BY PLANE SURFACES | RAY OPTICS... • TIR (OPTICAL FIBER & FISH VIEW) | RAY OPTI... 📚 Boost your physics concepts with clear explanations and practical examples. Don't forget to like, share, and subscribe for more educational content! 😊 #VariableRefractiveIndex #Optics #Physics #JEE #NEET #Boards #GradedIndex #Mirage #OpticalFibre 00:00 GLIMPSE 01:40 Introduction to Variable Refractive Index 06:00 Increasing Refractive index along Y axis 15:20 Decreasing Refractive index along Y axis 19:30 Increasing Refractive index along X axis 27:45 Equation of Trajectory 31:23 Sufficient thick glass slab 35:00 A ray enters a glass slab at an angle theta from air and the refractive index varies along the slab as u = u0-kt^2 where t is the distance measured along the normal 39:23 A ray of light enters into a thick glass slab from air as shown in figure the refractive index of the glass slab varies with the depth x from the top most surface of the slab Mu is equals to root 3 minus x by root 3 where x in metres slab is of sufficiently large thickness 43:13 Due to vertical temperature gradient in the atmosphere the index of refraction varies suppose index of refraction varies as n = n0sqrt(1 + a y) Where n0 is the index of refraction at the surface and a is equals to 2 into 10 power minus 6 m inverse a person of height 2 m stands on a level surface beyond what distance will he not see the runway 53:12 Along rectangular slab of transparent medium of thickness d is placed on a table with length parallel to x axis and with the parallel to y axis A Ray of light is travelling along y axis at origin the refractive index of the medium varies new equals to root 1 + e power x by D the refractive index of air is one determine the X coordinate of the point A where the ray intersects the upper surface of slab air boundary