Intersection of Two Arrays | Brute Force vs Hashing | LeetCode 349 скачать в хорошем качестве

Intersection of Two Arrays | Brute Force vs Hashing | LeetCode 349

Intersection of Two Arrays | Brute Force vs Hashing | LeetCode 349 In this video, we solve LeetCode 349 – Intersection of Two Arrays step by step. We’ll cover: ✔️ Naive brute force approach ✔️ Why nested loops are inefficient ✔️ Introduction to Hashing ✔️ Optimal solution using unordered_set ✔️ Time & Space Complexity analysis If you’re preparing for coding interviews, this problem is a great example of when to switch from brute force to hashing for faster lookup. 🧠 Key Concept: When you see: “Check if element exists” “Unique elements” “Avoid duplicates” Think → Hashing ⏱ Time Complexity: Naive → O(n * m) Optimal → O(n + m) 💻 Language Used: C++ This is part of my DSA interview preparation series where I break down problems into patterns to help you think like an interviewer. Subscribe for more LeetCode & DSA pattern videos 🚀