Critical Angle & TIR | JEE Mains 2026 Solution | 23 Jan Shift 1 | Ray Optics скачать в хорошем качестве

Critical Angle & TIR | JEE Mains 2026 Solution | 23 Jan Shift 1 | Ray Optics

Unlocking a tricky Ray Optics question from the JEE Mains 2026 (23 Jan, Shift 1) exam. We dive deep into the relationship between the speed of light, refractive index, and the critical angle. 🚀 Question: Consider light travelling from a medium A to medium B separated by a plane interface. If the light undergoes total internal reflection during its travel from medium A to B and the speed of light in media A and B are $2.4 \times 10^8$ m/s and $2.7 \times 10^8$ m/s, respectively, then the value of critical angle is: Options: 1. $\sin^{-1} (8/9)$ 2. $\cot^{-1} (3/\sqrt{13})$ 3. $\cos^{-1} (8/9)$ 4. $\tan^{-1} (8/\sqrt{17})$ 📌 Timestamps: 0:00 - Introduction to the problem 0:34 - Why does TIR happen? (Denser vs Rarer) 1:06 - Applying Snell's Law for Critical Angle 1:38 - Speed of light vs Refractive Index derivation 2:10 - Calculating $\sin i_c$ 2:25 - Converting $\sin$ to $\tan$ (The Triangle Method) 2:34 - Final Answer & Option 4 If you found this helpful, don't forget to Like, Share, and Subscribe to Physics Unlocked ⚛🔓! #JEEMains2026 #Physics #RayOptics #TIR #PhysicsUnlocked #IITJEE #ExamPreparation