exp(A)Bexp(-A) = B + [A,B] +1/2![A,[A,B]] +1/3![A,[A,[A,B]]]+... скачать в хорошем качестве

exp(A)Bexp(-A) = B + [A,B] +1/2![A,[A,B]] +1/3![A,[A,[A,B]]]+...

#Problems&SolutionsonQuantumMechanics: Prove that for A and B two operators, exp(A)Bexp(-A) = B + [A,B] +1/2![A,[A,B]] +1/3![A,[A,[A,B]]]+...... The famous identity or formula of quantum mechanical operator formalism has been proved herein. This is one of the most important identities, used in quantum mechanics. I feel extremely sorry as I forgot to write 1/3! with [A,[A,[A,B]]] at the end. Books recommended: Modern Quantum Mechanics by J. J. Sakurai and J. Napolitano Link: https://amzn.to/3DnZJyk Advanced Quantum Mechanics by J. J. Sakurai Link: https://amzn.to/3DqZr9V Introduction to Quantum Mechanics by Griffiths Link: https://amzn.to/3HEq4ee Hey! I am now making videos using the Samsung Galaxy S6 tab. It's highly recommended to use. If you are a grad student you can have this pocket-friendly one. You can use a cool keyboard alongside, which will facilitate ease of working. Link of this tab in amazon.in: https://amzn.to/3Fr00B5 Keyboard for Galaxy S6: https://amzn.to/3Hxmx0Y Pocket-friendly iPad: https://amzn.to/3Ficawa Camera used to shoot this video: Panasonic HC-V270 Super Zoom Full HD Camcorder, Black (Amazon link for SONY camcorder: https://amzn.to/3FEim1Z) Facebook Page:   / ayansarkaryoutube   Here's the amazon link to my new Dell Inspiron 3501 laptop: https://amzn.to/3FilqjU