LeetCode 1022 | Sum of Root To Leaf Binary Numbers | DFS | Java | Easy скачать в хорошем качестве

LeetCode 1022 | Sum of Root To Leaf Binary Numbers | DFS | Java | Easy

LeetCode 1022 – Sum of Root To Leaf Binary Numbers (Java) Today's LeetCode Daily You are given a binary tree where each node contains either 0 or 1. Each root to leaf path forms a binary number. Return the sum of all such numbers. Approach Used: Depth First Search Step 1: Traverse the tree using DFS. Step 2: Maintain currentValue while moving down. For each node: currentValue = currentValue multiplied by 2 plus node value. This simulates left shifting in binary and adding the current bit. Step 3: When a leaf node is reached, return the formed binary number. Step 4: Return sum of left subtree and right subtree. Key Idea: Treat path as a binary number. At each step: Shift left and add current bit. Time Complexity: O(n) Space Complexity: O(h) where h is height of tree. Problem Link: https://leetcode.com/problems/sum-of-... Java Solution (GitHub): https://github.com/Amandf/LeetCode-So... More daily Java solutions. Clean code. No mic. Pure logic. #leetcode #leetcodedailychallenge #java #binarytree #dfs #dsa #codinginterview #programming