6 Palindrome Linked List Explained Step-by-Step | Slow & Fast Pointer Technique | DSA using Java скачать в хорошем качестве

6 Palindrome Linked List Explained Step-by-Step | Slow & Fast Pointer Technique | DSA using Java

Confused about checking if a linked list is a palindrome? In this video, I explain the exact interview-optimized approach using slow & fast pointers, list reversal, and a clear dry run — step by step. In this video, you’ll learn how to check whether a singly linked list is a palindrome using the most efficient approach expected in coding interviews. We cover this problem from first principles, not shortcuts. ✅ What you’ll learn: What a palindrome linked list really means Why naive approaches (array / stack) are not optimal How the slow and fast pointer technique works How to reverse the second half of a linked list safely Step-by-step dry run with visuals Full Java implementation Edge cases interviewers love to test 📌 Problem Statement: Given the head of a singly linked list, determine whether the list is a palindrome. ⏱️ Time & Space Complexity: Time: O(n) Space: O(1) (no extra data structures) This explanation is perfect for: DSA beginners Java learners Coding interview preparation Anyone struggling with linked list pointers 📌 Subscribe & follow the playlist to build DSA the right way — from the system level.    • DSA with Java   📌Chapters 00:00 - Problem Statement 00:25 - Algorithm 02:02 - Step 1: Finding the Middle Node 04:00 - Step 2: Reverse the Second Half 05:02 - Step 3: Compare Both Halves 07:01 - Full Code: Node Definition 07:10 - Finding Middle Node 08:44 - Reverse Second Half 09:33 - Compare both halves 10:52 - Restore the List 12:57 - Outro Like, share, and subscribe if this clarified a concept that confused you earlier.