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#modelmaking #crafting #miniature #minipainting Patreon: / scifi_crafts Website: https://scifi-miniatures.jimdosite.com/ FB: / scificrafts Calculation: When your LED needs 3.3V and you have a battery like mine delivering 4.2V, you gotta get rid of 0.9V! So its R = U / I The current most of those "superbright" LEDs need is 20mA = 0.02A U = 4.2 - 3.3V = 0.9V R = 0.9V / 0.02A = 45 Ohm You just pick the next best value which is 47 Ohm. Plus minus 2 Ohms won't hurt. Same calc, done with a red 2.2V LED: U = 4.2V - 2.2V = 2V R = 2V / 0.02V =100 Ohm IF you wanna run this on a lets say 12V battery pack, you go: 12V - 3.3V = 8.7V you gotta get rid of. Same thing, devided by current flowing...still 20mA for a SINGLE LED. R = 8.7V / 0.02A = 435 Ohm I use 470 Ohm reistors in that case. If you put together two or more LEDs in series, which means you connect one plus-pin of the first LED to the minus-pin of the second (and so on), they need 6.6V....means they only need one resistor which is of lower value. I can show that in another video. Material/tools list: your hands, cotton, acrylic 4x4mm rod, black spraypaint (non water based), 1.8mm blue LED, 3 / 5mm yellow LED, 5mm orange LED, hot glue, solder, resistors 47 Ohm (2) and 100 Ohm (1)