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#globalmathinstiute #anilkumarmath Test Question: • Absolute Maximum Minimum Closed Interval M... Playlist: • Calculus Extreme Value Theorem in Closed I... / @mathematicstutor Anil Kumar Math Classes: https://www.globalmathinstitute.com/c... For Guidance Contact : [email protected] • 2x^5/3 - 5x^2/3 [-8, 2] Absolute Maximum M... a. Graph a cubic function with absolute minimum at (-2, -10), local maximum at (0, 4), local minimum at (2, -2) and absolute maximum at (4, 11). b. What is the domain and range of this function? c. Write the increasing/decreasing interval for the function. Absolute Maximum and Absolute minimum value for any function continuous in closed interval [a, b] will always exist at the critical numbers or at the end points. Check the value of the function at the critical numbers and at the end-points to find the result. Increasing Decreasing Interval Details: • Test Series Increasing Decreasing Interval... Steps to find increasing and decreasing interval of any function, f(x), are: find the first derivative, f'(x) find critical numbers, f'(x) = 0 or does not exist (DNE) INTERVAL TABLE TEST: These critical numbers divide the domain in intervals. Test each interval with a test point. RESULT: If f'(x) is greater than 0 then f(x) is increasing. If f'(x) is less than 0 then f(x) is decreasing. For Guidance Contact : [email protected] or Enrol at Global Math Institute: https://www.globalmathinstitute.com/c... #calculus #derivativeapplication #increasinginterval #decreasinginterval #mcv4u #anilkumar #globalmathinstitute #absolutemaximum #absoluteminimum