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LeetCode 1680 – Concatenation of Consecutive Binary Numbers | Bit Manipulation Interview Approach In this video, we solve LeetCode 1680 using an optimal Bit Manipulation strategy instead of brute force string concatenation. The problem asks us to concatenate the binary representations of numbers from 1 to n and return the decimal value modulo 10^9 + 7. A naive string approach may work for small inputs, but for large n it leads to inefficiency. In this solution, we: Understand the core binary pattern Learn how left shift works while appending bits Avoid building long strings Optimize the approach to O(n) time Handle modulo carefully to prevent overflow Example explained step by step: n = 3 → binary sequence: 1, 10, 11 Concatenated: 11011 → Decimal = 27 This video is perfect for: LeetCode Daily practice Bit Manipulation revision Interview preparation Improving binary logic thinking If you're preparing for coding interviews or placements, this is a must-understand concept. Stay consistent. Solve daily. Think in bits. 🚀 💻 Source Code & Repository 🔗 Main LeetCode Repository: 👉 https://github.com/Gopalkushwaha1/Lee... 📂 Problem Folder (1680 – Concatenation of Consecutive Binary Numbers): 👉 https://github.com/Gopalkushwaha1/Lee... 🧠 Direct Java Solution Code: 👉 https://github.com/Gopalkushwaha1/Lee... 🚀 If you're preparing for coding interviews or placements, make sure to check the full repository for more optimized LeetCode solutions. #LeetCode1680 #BitManipulation #CodingInterview #LeetCodeSolution