4 Electric field due to Point Charge and Ring | Electrostatics Class 12 | JEE Mains & Advanced скачать в хорошем качестве

4 Electric field due to Point Charge and Ring | Electrostatics Class 12 | JEE Mains & Advanced

🎓Watch Complete YouTube Lectures Distraction-Free Download the Competishun App 👉 https://play.google.com/store/apps/de... 🌐 Login for Courses & Test Series: 👉 https://i.competishun.com/ Popular Courses for IIT-JEE: Pratham | Prakhar | Prakhar Integrated I | Praveen | Pragyaan C3 | Champ | CATS | ABC | PYQ Express UTS | ATS 👉 Explore all: https://competishun.com/courses/ 📞 Support: 8888-0000-21 | 7410-900-901 | 7410-900-908 --------------Topics and Problems covered in this Electrostatics (class 12)lecture by ABJ sir IITD with time stamp: 00:00 - 04:05 Electric Field due to Point charge: Derivation of Formulae, Graph of Electric field wrt position. The electric field due to point charge is inversely proportional to the square of the distance of the point at which the electric field is measured. 04:05 - 07:29 Vector form of the electric field due to point charge 07:29 - 10:11 Electrostatic problem 1: Based on the electric field due to point charge: To find the electric field in vector form, if coordinates of the charge and point, at which the electric field is measured, are given. 10:54 - 25:27 Electrostatic problem 2: To find the net electric field due to two charges and draw its curve wrt position, if both charges have the same polarity 25:27 - 33:45 Electrostatic problem 3: to find the net electric field due to two charges and draw its curve wrt position, if both charge have opposite polarity 33:50 - 54:20 Electric field due to Uniform Ring: Derivation of Formulae of electric field due to ring at different points. 52:25 - 54:30 Graph of Electric field due to ring wrt position of the point at which electric field is measured 54:30 - 01:03:11 Electrostatic problem 4: Based on the electric field due to Ring & concept of SHM: To prove that electron is displaced slightly along axis, it will perform SHM. Also, to find the time period of SHM 01:03:17 - 01:12:37 Electrostatic problem 5: To find the electrostatic force between a rod and a ring, if the rod is placed horizontally on the axis of ring and one end point of the rod is at the center of the ring. 01:12:37 - 01:22:00 Electric field due to uniform half ring & Quarter ring: Derivation 01:22:45 - 01:32:42 Electrostatic problem 6: Advanced Problem on E.F. due to Half ring at a point P which is at the some distance from the plane of the ring. Free IIT JEE coaching, Free JEE Main lectures, Best IIT JEE YouTube channel, Complete JEE syllabus free, Free online coaching for JEE, Free JEE Main and Advanced preparation, Best free lectures for JEE, IIT JEE physics, chemistry, math full syllabus, Best YouTube channel for JEE Main, Free JEE Main physics lectures, Best coaching for JEE Main and Advanced, JEE Main revision lectures free, Top quality IIT JEE preparation, IIT JEE full syllabus free lectures, JEE Advanced full syllabus crash course, Free coaching videos for IIT aspirants, Best online content for JEE aspirants, Free JEE coaching by IITians, Complete JEE course on YouTube, Free mock tests and revision for JEE, #JEEMain #JEEAdvanced #Competishun #Physics #MohitTyagi