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Learn how to resolve the common `NavigationLink` error by using `Link` to safely redirect users to a website in SwiftUI. --- This video is based on the question https://stackoverflow.com/q/72815173/ asked by the user 'T.Jaggard' ( https://stackoverflow.com/u/7251714/ ) and on the answer https://stackoverflow.com/a/72815306/ provided by the user 'lorem ipsum' ( https://stackoverflow.com/u/12738750/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions. Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: NavigationLink issue linking to a website Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l... The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license. If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com. --- Navigating to External Websites in SwiftUI: The NavigationLink Issue If you are a developer working with SwiftUI, you might have come across an issue while trying to link to a website using NavigationLink. The specific error message that can be frustrating is: "Generic struct 'NavigationLink' requires that 'URL' conform to 'View'." This can be particularly perplexing, especially if you're not sure why the standard methods for creating links aren’t working as anticipated. Let's break down this issue and find an appropriate solution. Understanding the Problem When you try to create a button that directs users to an external website (like Google) using the following code: [[See Video to Reveal this Text or Code Snippet]] You may receive an error. The core of the problem lies in the fact that NavigationLink is designed to work with SwiftUI Views, not with basic URL types. In other words, NavigationLink is meant to navigate between different views within your app, and since URL is not a View, the compiler throws the error. The Solution: Utilizing Link Instead To resolve this issue, a simple switch from NavigationLink to Link can be your saving grace. The Link view is specifically designed for this purpose: it creates a hyperlink that opens up URLs in Safari or the default web browser on a device. Let's delve into how to implement this correctly. Step-by-Step Implementation Here’s how you can modify your code to use Link instead of NavigationLink: Replace NavigationLink: Change your code from using NavigationLink to Link. Provide the URL: Pass in the URL string directly to Link as follows: [[See Video to Reveal this Text or Code Snippet]] Example in Context Here’s how your SwiftUI view might now look using Link: [[See Video to Reveal this Text or Code Snippet]] Advantages of Using Link Simplicity: It provides a straightforward way to open URLs. Compatibility: Specifically built to work seamlessly with web links. User Experience: Engages the built-in browser for external content without complex navigation. Conclusion By simply switching from NavigationLink to Link, you can easily create buttons that redirect users to websites through Safari without facing the dreaded error. This not only streamlines your code but enhances the overall user experience by managing external links seamlessly. Don't hesitate to implement Link in your SwiftUI projects for all your hyperlink needs! Now that you know how to handle web links in your SwiftUI apps, you can navigate external content with ease and confidence. Happy coding!