Compound Manometer Problem and Solution (Find Pressure with 3 Different Liquids) скачать в хорошем качестве

Compound Manometer Problem and Solution (Find Pressure with 3 Different Liquids)

Lets do a compound manometer problem . We are given a diagram of a manometer the pressure of the atmosphere the height differences and specific weights of 3 fluids in the manometer. Before I begin I want to stress the importance of making sure that you have converted all units to your desired end units of pressure. So in this case all units are converted to newtons and meters so we can get a final pressure in newtons per meter squared also known as a pascal. So lets first go over the reasoning behind adding or subtracting pressure in a manometer. If there is more fluid on one side of the manometer tube that fluid will be exerting a greater force downward than the opposite side. This either causes a pressure increase or pressure decrease. For a U bend if there is more liquid on the end with given pressure that liquid must be exerting a force towards the end we are solving the pressure for. In this case we add pressure or the specific weight times height to get the final pressure. If there is more liquid on the end we are solving for than that liquid must be exerting a force towards the given pressure end. We must subtract the pressure to get the final pressure at the end we are solving for. Similarly for a n bend pipe if there is more liquid on the end we are solving for than that liquid must be exerting a force towards that end. The pressure in the solving end increases and we must add the specific weight times height or pressure to get the pressure we are solving for. If there is more liquid on the end we are given the pressure for that liquid must be exerting a force towards the given end. We subtract the specific weight times height or pressure in this case to get the final pressure at the end we are solving for. So now that we understand how the pressure increase and decreased work in a manometer let go back the problem. To start off we have atmospheric pressure pushing towards the end we are solving for so we must add this value to get final pressure To help as a visual aid I will be showing a manometer laid out flat and the directions of the force in both the original diagram and the flat diagram. Than we have the mercury which has more liquid on the side opposite of what we are solving for. This liquid is exerting a force towards the end we are solving for. We must add the specific weight time height to get the final pressure. After that we see the diesel that has more liquid at the end opposite of the end we are solving for. We can see that this liquid will exert a force going towards the open end. We must subtract the specific weight times the height. Now finally we hit the water. There is more water on the side we are solving for. This means that that water is exerting a force outwards towards the open end. We must subtract the specific weight of water times the height difference. So after so after adding and subtracting all of the values we get that the air inside the tank is 260,565 N/m^2 Hopefully this video help thanks for watching hopefully I earned a like share or subscription. Disclaimer These videos are intended for educational purposes only (students trying to pass a class) If you design or build something based off of these videos you do so at your own risk. I am not a professional engineer and this should not be considered engineering advice. Consult an engineer if you feel you may put someone at risk.