Let y=y(x) be the solution of the differential equation x⁴ dy + (4x³y + 2 sin x) dx = 0 || JEE MAIN скачать в хорошем качестве

Let y=y(x) be the solution of the differential equation x⁴ dy + (4x³y + 2 sin x) dx = 0 || JEE MAIN

Let y=y(x) be the solution of the differential equation x⁴ dy + (4x³y + 2 sin x) dx = 0, y(π/2) = 0. Then y(π/3) is equal to: (1) 72 (2) 92 (3) 64 (4) 81 In this video you will learn: • How to solve first order differential equations • Using linear differential equation methods • Applying initial conditions in differential equations • Quick tricks for solving JEE Main calculus problems This question is very useful for students preparing for: JEE Main 2026 JEE Main 2027 JEE Advanced Mathematics Watch the full video to see the complete step-by-step solution with a clear concept explanation. Tags: jee main 2026 maths question, jee main 23 january shift 1 solution, differential equation jee main, calculus jee main solved questions, jee maths previous year question, first order differential equation jee, jee main maths pyq solution, jee maths tricks Hashtags: #JEEMain2026 #JEE2026 #JEEMaths #DifferentialEquation #Calculus #MathsTricks #JEEPreparation #EngineeringEntrance