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In this video, we solve the “Find Smallest Letter Greater Than Target” problem using Binary Search. You are given a sorted list of characters and a target character. Your task is to find the smallest character strictly greater than the target. If no such character exists, you simply wrap around and return the first character in the list. 💻 Code Link (LeetCode Solution) 👉 https://leetcode.com/problems/find-sm... --- System Design Playlist (Swiggy Case Study) 👉 • System Design: Food Delivery App (Swiggy /... --- 💡 Key Intuition Since the list is sorted, binary search gives us the most efficient solution. We: Move right when letters[mid] less than equal to target Move left when letters[mid] greater than target After binary search: If the index goes out of bounds → return the first letter Otherwise → return the letter at that index This approach avoids unnecessary linear scans and runs in O(log n) time. Topics Covered Binary Search on characters Wrap-around logic Edge cases explained Clean and interview-ready Python solution ⏱ Complexity Analysis Time Complexity: O(log n) Space Complexity: O(1) --- 🚀 Perfect For Coding interviews LeetCode practice Beginners learning Binary Search FAANG / Product-based company prep 👍 *Like, Share & Subscribe* for more DSA and System Design content! #LeetCode744 #FindSmallestLetterGreaterThanTarget #BinarySearch #EasyLeetCode #LeetCodeDaily #BinarySearchProblems #InterviewPreparation #FAANG #DSA #StudyPlacement #CodingInterview #LowerBound #SortedArray #CompetitiveProgramming